Re: For all you Futurama mathoids out there...

That Guy  wrote:

> Don Del Grande wrote:
>
>> That Guy wrote:
>>
>>> What's a perfect cube?
>>
>> Seriously?  An integer that is an integer multiplied by itself, and
>> then multiplied by itself again.
>
>Ok, so that would be 'perfect' cube being the cube of an integer as
opposed 
>to a 'regular' cube which could be a number like 3.241 or 88 2/3
multiplied 
>by itself and then by itself again?

Correct.

>Why does a bender number have to be the sum of two perfect cubes?  Why
can't 
>it be any integer that's the sum of any two cubes?  I'm assuming the sum 
>itself has to be an integer because a bending unit isn't likely to have a

>non-integer as a unit number... 

Every real number has a real cube root, so for any integer N, if A + B
= N, then (the cube root of A) cubed + (the cube root of B) cubed = N,
so every integer would be a Bender number.

-- Don