"Don Del Grande" <del_grande_news@[EMAIL PROTECTED]
> wrote in message
news:g6hjm3le5ruqtb251u35otppff58u3et84@[EMAIL PROTECTED]
> That Guy wrote:
>
>> Don Del Grande wrote:
>>
>>> That Guy wrote:
>>>
>>>> What's a perfect cube?
>>>
>>> Seriously? An integer that is an integer multiplied by itself, and
>>> then multiplied by itself again.
>>
>>Ok, so that would be 'perfect' cube being the cube of an integer as
>>opposed
>>to a 'regular' cube which could be a number like 3.241 or 88 2/3
>>multiplied
>>by itself and then by itself again?
>
> Correct.
>
>>Why does a bender number have to be the sum of two perfect cubes? Why
>>can't
>>it be any integer that's the sum of any two cubes? I'm assuming the sum
>>itself has to be an integer because a bending unit isn't likely to have
a
>>non-integer as a unit number...
>
> Every real number has a real cube root, so for any integer N, if A + B
> = N, then (the cube root of A) cubed + (the cube root of B) cubed = N,
> so every integer would be a Bender number.
>
> -- Don
I actually understand that, and I only had to read it twice. If you knew
what level my math comprehension is at, you'd know what a huge compliment
that is. Are you a teacher?
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