"Jim Gysin" <jimgysin@[EMAIL PROTECTED]
> wrote in message
news:kn4924hh2n2f8tks9oeerouui2fkmn29ca@[EMAIL PROTECTED]
> In Thursday's episode, Sayid was told by Gault that (according to
> Faraday) a bearing of 305 is the only safe way to get "to and from the
> boat."
>
> In the season two finale, Michael was told to follow a bearing of 325
> *from* the island to "find rescue."
>
> If things are stationary (as in the island is not spinning, or some
> such thing) and a bearing of 325 takes you safely *away* from the
> island (as it seemed to do for Michael), wouldn't it be most likely
> that to get safely *to* the island you would want to follow a course
> of 035?
>
> Furthermore, if a course of 305 is the only safe way to get to *and*
> from the boat, wouldn't a person have to cir***navigate the globe at
> some point in order to safely take a trip from the island to the boat
> and back to island again? And isn't Sayid already in the middle of
> such a trip? Will he have to travel 99.9% of the way around the globe
> in the Zodiac, or should we assume that they all did that on the way
> in on the chopper? Or are the rules different if you're airborne,
> rather than at sea level?
>
> And doesn't the Gault/Faraday line also suggest that there's something
> funky going on with the freighter, rather than (or in addition to)
> whatever's going on with the island? Otherwise, why would there be
> only one safe way to get to and from the *boat*? Until now, I
> accepted the fact that there may only one safe way to get to and from
> the *island*, but the same applies to the boat? That's very strange.
>
Didn't this episode also tell us that the Island is capable of moving?
Therefore bearings to and from the Island are capable of changing too, I
should imagine.
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